Solution: Let $f(x_1,x_2)= 5x_1 + 2x_2$. We will use graphical method to solve this linear programming problem (LPP). Look at the figure below.
Now the minimum value of the objective function will be on the axes in the feasible region. Let us substitute the value and see which one is corresponding to the minimum.
\begin{align*}
f(1,0) & = 5 \\
f(0,1) & = 2 \\
f(0,2) & = 4.
\end{align*}
Thus, the minimum value of the LPP is $2$ and the corresponding value of point will be $(0,1)$.