Solution: Consider the function
\[
f : (0,\infty ) \to \mathbb{R} , \quad f(x) = \frac{1}{x}.
\]
It is clear that the function is continuous on $(0, \infty )$. We take a sequence $\left( \frac{1}{n} \right) $, which is convergent in $\mathbb{R} $ and hence Cauchy. The image
\[
f\left( \frac{1}{n} \right) = n,
\]
is not Cauchy.